Base | Representation |
---|---|
bin | 1110110110000100001… |
… | …1101011011001100011 |
3 | 220101021120121201010221 |
4 | 3231201003223121203 |
5 | 13134301021041421 |
6 | 313054304303511 |
7 | 24265626225115 |
oct | 3554103533143 |
9 | 811246551127 |
10 | 255031424611 |
11 | 99181655007 |
12 | 41515611b97 |
13 | 1b0845a1012 |
14 | c4b4b333b5 |
15 | 69798cb841 |
hex | 3b610eb663 |
255031424611 has 2 divisors, whose sum is σ = 255031424612. Its totient is φ = 255031424610.
The previous prime is 255031424513. The next prime is 255031424623. The reversal of 255031424611 is 116424130552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255031424611 - 233 = 246441490019 is a prime.
It is a super-3 number, since 3×2550314246113 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (255031424311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127515712305 + 127515712306.
It is an arithmetic number, because the mean of its divisors is an integer number (127515712306).
Almost surely, 2255031424611 is an apocalyptic number.
255031424611 is a deficient number, since it is larger than the sum of its proper divisors (1).
255031424611 is an equidigital number, since it uses as much as digits as its factorization.
255031424611 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
The spelling of 255031424611 in words is "two hundred fifty-five billion, thirty-one million, four hundred twenty-four thousand, six hundred eleven".
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