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2550315203041 is a prime number
BaseRepresentation
bin100101000111001010101…
…000011011100111100001
3100000210210211222201010011
4211013022220123213201
5313241021142444131
65231333145404521
7352153121356444
oct45071250334741
910023724881104
102550315203041
118a364549a011
12352327499741
13156655843828
148b61621365b
1546515eb90b1
hex251caa1b9e1

2550315203041 has 2 divisors, whose sum is σ = 2550315203042. Its totient is φ = 2550315203040.

The previous prime is 2550315203039. The next prime is 2550315203047. The reversal of 2550315203041 is 1403025130552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2222696338641 + 327618864400 = 1490871^2 + 572380^2 .

It is a cyclic number.

It is not a de Polignac number, because 2550315203041 - 21 = 2550315203039 is a prime.

Together with 2550315203039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2550315202994 and 2550315203012.

It is not a weakly prime, because it can be changed into another prime (2550315203047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275157601520 + 1275157601521.

It is an arithmetic number, because the mean of its divisors is an integer number (1275157601521).

Almost surely, 22550315203041 is an apocalyptic number.

It is an amenable number.

2550315203041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2550315203041 is an equidigital number, since it uses as much as digits as its factorization.

2550315203041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18000, while the sum is 31.

The spelling of 2550315203041 in words is "two trillion, five hundred fifty billion, three hundred fifteen million, two hundred three thousand, forty-one".