Base | Representation |
---|---|
bin | 111001111111001110010011… |
… | …001010011011101111110111 |
3 | 1020102222221121102001021201011 |
4 | 321333032103022123233313 |
5 | 231411431231001230111 |
6 | 2302224410105013051 |
7 | 104501356500430105 |
oct | 7177162312335767 |
9 | 1212887542037634 |
10 | 255033332055031 |
11 | 74297035270212 |
12 | 2472b202a84187 |
13 | ac3c7035649aa |
14 | 46d9971780c75 |
15 | 1e74007830021 |
hex | e7f39329bbf7 |
255033332055031 has 2 divisors, whose sum is σ = 255033332055032. Its totient is φ = 255033332055030.
The previous prime is 255033332055017. The next prime is 255033332055037. The reversal of 255033332055031 is 130550233330552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255033332055031 - 25 = 255033332054999 is a prime.
It is a super-2 number, since 2×2550333320550312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255033332055037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127516666027515 + 127516666027516.
It is an arithmetic number, because the mean of its divisors is an integer number (127516666027516).
Almost surely, 2255033332055031 is an apocalyptic number.
255033332055031 is a deficient number, since it is larger than the sum of its proper divisors (1).
255033332055031 is an equidigital number, since it uses as much as digits as its factorization.
255033332055031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 607500, while the sum is 40.
Adding to 255033332055031 its reverse (130550233330552), we get a palindrome (385583565385583).
The spelling of 255033332055031 in words is "two hundred fifty-five trillion, thirty-three billion, three hundred thirty-two million, fifty-five thousand, thirty-one".
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