Base | Representation |
---|---|
bin | 111001111111011000011011… |
… | …000001000011011100010111 |
3 | 1020110000222122220022200200201 |
4 | 321333120123001003130113 |
5 | 231412121011003412101 |
6 | 2302233404421121331 |
7 | 104502223031054122 |
oct | 7177303301033427 |
9 | 1213028586280621 |
10 | 255044201232151 |
11 | 742a0702674921 |
12 | 24731336b59247 |
13 | ac40746346146 |
14 | 46da2c31193b9 |
15 | 1e74441b7be01 |
hex | e7f61b043717 |
255044201232151 has 2 divisors, whose sum is σ = 255044201232152. Its totient is φ = 255044201232150.
The previous prime is 255044201232103. The next prime is 255044201232157. The reversal of 255044201232151 is 151232102440552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255044201232151 - 223 = 255044192843543 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 255044201232151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255044201232157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127522100616075 + 127522100616076.
It is an arithmetic number, because the mean of its divisors is an integer number (127522100616076).
Almost surely, 2255044201232151 is an apocalyptic number.
255044201232151 is a deficient number, since it is larger than the sum of its proper divisors (1).
255044201232151 is an equidigital number, since it uses as much as digits as its factorization.
255044201232151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96000, while the sum is 37.
The spelling of 255044201232151 in words is "two hundred fifty-five trillion, forty-four billion, two hundred one million, two hundred thirty-two thousand, one hundred fifty-one".
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