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255044315213 is a prime number
BaseRepresentation
bin1110110110000111010…
…0110110100001001101
3220101022110212121201122
43231201310312201031
513134312321041323
6313055444450325
724266143624052
oct3554164664115
9811273777648
10255044315213
11991889599a6
12415199a99a5
131b0871654ac
14c4b672b029
15697aac5ec8
hex3b61d3684d

255044315213 has 2 divisors, whose sum is σ = 255044315214. Its totient is φ = 255044315212.

The previous prime is 255044315191. The next prime is 255044315221. The reversal of 255044315213 is 312513440552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 252338442889 + 2705872324 = 502333^2 + 52018^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255044315213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255044311213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127522157606 + 127522157607.

It is an arithmetic number, because the mean of its divisors is an integer number (127522157607).

Almost surely, 2255044315213 is an apocalyptic number.

It is an amenable number.

255044315213 is a deficient number, since it is larger than the sum of its proper divisors (1).

255044315213 is an equidigital number, since it uses as much as digits as its factorization.

255044315213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 255044315213 its reverse (312513440552), we get a palindrome (567557755765).

The spelling of 255044315213 in words is "two hundred fifty-five billion, forty-four million, three hundred fifteen thousand, two hundred thirteen".