Base | Representation |
---|---|
bin | 1110110110000111010… |
… | …0110110100001001101 |
3 | 220101022110212121201122 |
4 | 3231201310312201031 |
5 | 13134312321041323 |
6 | 313055444450325 |
7 | 24266143624052 |
oct | 3554164664115 |
9 | 811273777648 |
10 | 255044315213 |
11 | 991889599a6 |
12 | 415199a99a5 |
13 | 1b0871654ac |
14 | c4b672b029 |
15 | 697aac5ec8 |
hex | 3b61d3684d |
255044315213 has 2 divisors, whose sum is σ = 255044315214. Its totient is φ = 255044315212.
The previous prime is 255044315191. The next prime is 255044315221. The reversal of 255044315213 is 312513440552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 252338442889 + 2705872324 = 502333^2 + 52018^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255044315213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255044311213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127522157606 + 127522157607.
It is an arithmetic number, because the mean of its divisors is an integer number (127522157607).
Almost surely, 2255044315213 is an apocalyptic number.
It is an amenable number.
255044315213 is a deficient number, since it is larger than the sum of its proper divisors (1).
255044315213 is an equidigital number, since it uses as much as digits as its factorization.
255044315213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 255044315213 its reverse (312513440552), we get a palindrome (567557755765).
The spelling of 255044315213 in words is "two hundred fifty-five billion, forty-four million, three hundred fifteen thousand, two hundred thirteen".
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