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255044315231 is a prime number
BaseRepresentation
bin1110110110000111010…
…0110110100001011111
3220101022110212121202022
43231201310312201133
513134312321041411
6313055444450355
724266143624106
oct3554164664137
9811273777668
10255044315231
1199188959a12
12415199a99bb
131b0871654c4
14c4b672b03d
15697aac5edb
hex3b61d3685f

255044315231 has 2 divisors, whose sum is σ = 255044315232. Its totient is φ = 255044315230.

The previous prime is 255044315221. The next prime is 255044315249. The reversal of 255044315231 is 132513440552.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255044315231 - 218 = 255044053087 is a prime.

It is a super-2 number, since 2×2550443152312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255044315191 and 255044315200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255044315221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127522157615 + 127522157616.

It is an arithmetic number, because the mean of its divisors is an integer number (127522157616).

Almost surely, 2255044315231 is an apocalyptic number.

255044315231 is a deficient number, since it is larger than the sum of its proper divisors (1).

255044315231 is an equidigital number, since it uses as much as digits as its factorization.

255044315231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 255044315231 its reverse (132513440552), we get a palindrome (387557755783).

The spelling of 255044315231 in words is "two hundred fifty-five billion, forty-four million, three hundred fifteen thousand, two hundred thirty-one".