Base | Representation |
---|---|
bin | 1110110110000111010… |
… | …0110110100001011111 |
3 | 220101022110212121202022 |
4 | 3231201310312201133 |
5 | 13134312321041411 |
6 | 313055444450355 |
7 | 24266143624106 |
oct | 3554164664137 |
9 | 811273777668 |
10 | 255044315231 |
11 | 99188959a12 |
12 | 415199a99bb |
13 | 1b0871654c4 |
14 | c4b672b03d |
15 | 697aac5edb |
hex | 3b61d3685f |
255044315231 has 2 divisors, whose sum is σ = 255044315232. Its totient is φ = 255044315230.
The previous prime is 255044315221. The next prime is 255044315249. The reversal of 255044315231 is 132513440552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255044315231 - 218 = 255044053087 is a prime.
It is a super-2 number, since 2×2550443152312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 255044315191 and 255044315200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255044315221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127522157615 + 127522157616.
It is an arithmetic number, because the mean of its divisors is an integer number (127522157616).
Almost surely, 2255044315231 is an apocalyptic number.
255044315231 is a deficient number, since it is larger than the sum of its proper divisors (1).
255044315231 is an equidigital number, since it uses as much as digits as its factorization.
255044315231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 255044315231 its reverse (132513440552), we get a palindrome (387557755783).
The spelling of 255044315231 in words is "two hundred fifty-five billion, forty-four million, three hundred fifteen thousand, two hundred thirty-one".
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