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2550449131 is a prime number
BaseRepresentation
bin1001100000000100…
…1100001111101011
320120202010020110221
42120001030033223
520210403333011
61101024550511
7120126313516
oct23001141753
96522106427
102550449131
1110997311aa
125b2182437
133185140c9
141a2a23d7d
15edd93971
hex9804c3eb

2550449131 has 2 divisors, whose sum is σ = 2550449132. Its totient is φ = 2550449130.

The previous prime is 2550449113. The next prime is 2550449137. The reversal of 2550449131 is 1319440552.

Together with previous prime (2550449113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2550449131 - 27 = 2550449003 is a prime.

It is a super-2 number, since 2×25504491312 = 13009581539637310322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2550449137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275224565 + 1275224566.

It is an arithmetic number, because the mean of its divisors is an integer number (1275224566).

Almost surely, 22550449131 is an apocalyptic number.

2550449131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2550449131 is an equidigital number, since it uses as much as digits as its factorization.

2550449131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 34.

The square root of 2550449131 is about 50501.9715555739. The cubic root of 2550449131 is about 1366.2774126874.

Adding to 2550449131 its reverse (1319440552), we get a palindrome (3869889683).

The spelling of 2550449131 in words is "two billion, five hundred fifty million, four hundred forty-nine thousand, one hundred thirty-one".