Base | Representation |
---|---|
bin | 1110110110001000101… |
… | …1001011000000101001 |
3 | 220101022212212212221001 |
4 | 3231202023023000221 |
5 | 13134320320310223 |
6 | 313100214115001 |
7 | 24266244433465 |
oct | 3554213130051 |
9 | 811285785831 |
10 | 255050166313 |
11 | 99191195a18 |
12 | 4151b94ba61 |
13 | 1b088433797 |
14 | c4b74114a5 |
15 | 697b37e9ad |
hex | 3b622cb029 |
255050166313 has 2 divisors, whose sum is σ = 255050166314. Its totient is φ = 255050166312.
The previous prime is 255050166311. The next prime is 255050166379. The reversal of 255050166313 is 313661050552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 236674466064 + 18375700249 = 486492^2 + 135557^2 .
It is a cyclic number.
It is not a de Polignac number, because 255050166313 - 21 = 255050166311 is a prime.
Together with 255050166311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (255050166311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127525083156 + 127525083157.
It is an arithmetic number, because the mean of its divisors is an integer number (127525083157).
Almost surely, 2255050166313 is an apocalyptic number.
It is an amenable number.
255050166313 is a deficient number, since it is larger than the sum of its proper divisors (1).
255050166313 is an equidigital number, since it uses as much as digits as its factorization.
255050166313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 37.
The spelling of 255050166313 in words is "two hundred fifty-five billion, fifty million, one hundred sixty-six thousand, three hundred thirteen".
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