Base | Representation |
---|---|
bin | 1001100000001101… |
… | …0101011011010111 |
3 | 20120210011210021001 |
4 | 2120003111123113 |
5 | 20211024323111 |
6 | 1101045004131 |
7 | 120134143642 |
oct | 23003253327 |
9 | 6523153231 |
10 | 2551011031 |
11 | 1099a85388 |
12 | 5b23b3647 |
13 | 31867caaa |
14 | 1a2b2ca59 |
15 | ede551c1 |
hex | 980d56d7 |
2551011031 has 2 divisors, whose sum is σ = 2551011032. Its totient is φ = 2551011030.
The previous prime is 2551011019. The next prime is 2551011037. The reversal of 2551011031 is 1301101552.
2551011031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2551011031 - 215 = 2550978263 is a prime.
It is a super-2 number, since 2×25510110312 = 13015314560567365922, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2551011037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1275505515 + 1275505516.
It is an arithmetic number, because the mean of its divisors is an integer number (1275505516).
Almost surely, 22551011031 is an apocalyptic number.
2551011031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2551011031 is an equidigital number, since it uses as much as digits as its factorization.
2551011031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 19.
The square root of 2551011031 is about 50507.5343983450. The cubic root of 2551011031 is about 1366.3777420629.
Adding to 2551011031 its reverse (1301101552), we get a palindrome (3852112583).
The spelling of 2551011031 in words is "two billion, five hundred fifty-one million, eleven thousand, thirty-one".
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