Base | Representation |
---|---|
bin | 111010000000100001000000… |
… | …100010101010100100010001 |
3 | 1020110022102211121021001211111 |
4 | 322000201000202222210101 |
5 | 231414410120343231343 |
6 | 2302333254312013321 |
7 | 104510652315336103 |
oct | 7200410042524421 |
9 | 1213272747231744 |
10 | 255122140211473 |
11 | 74320768146627 |
12 | 24744468691241 |
13 | ac47bb748a1a2 |
14 | 46ddd98273573 |
15 | 1e764a4232c9d |
hex | e808408aa911 |
255122140211473 has 2 divisors, whose sum is σ = 255122140211474. Its totient is φ = 255122140211472.
The previous prime is 255122140211431. The next prime is 255122140211483. The reversal of 255122140211473 is 374112041221552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 192311633316609 + 62810506894864 = 13867647^2 + 7925308^2 .
It is a cyclic number.
It is not a de Polignac number, because 255122140211473 - 245 = 219937768122641 is a prime.
It is not a weakly prime, because it can be changed into another prime (255122140211483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561070105736 + 127561070105737.
It is an arithmetic number, because the mean of its divisors is an integer number (127561070105737).
Almost surely, 2255122140211473 is an apocalyptic number.
It is an amenable number.
255122140211473 is a deficient number, since it is larger than the sum of its proper divisors (1).
255122140211473 is an equidigital number, since it uses as much as digits as its factorization.
255122140211473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 134400, while the sum is 40.
The spelling of 255122140211473 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, four hundred seventy-three".
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