Base | Representation |
---|---|
bin | 111010000000100001000000… |
… | …100010101010100011100111 |
3 | 1020110022102211121021001202221 |
4 | 322000201000202222203213 |
5 | 231414410120343231211 |
6 | 2302333254312013211 |
7 | 104510652315336013 |
oct | 7200410042524347 |
9 | 1213272747231687 |
10 | 255122140211431 |
11 | 74320768146599 |
12 | 24744468691207 |
13 | ac47bb748a16c |
14 | 46ddd98273543 |
15 | 1e764a4232c71 |
hex | e808408aa8e7 |
255122140211431 has 2 divisors, whose sum is σ = 255122140211432. Its totient is φ = 255122140211430.
The previous prime is 255122140211417. The next prime is 255122140211473. The reversal of 255122140211431 is 134112041221552.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255122140211431 is a prime.
It is a super-2 number, since 2×2551221402114312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255122140211131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561070105715 + 127561070105716.
It is an arithmetic number, because the mean of its divisors is an integer number (127561070105716).
Almost surely, 2255122140211431 is an apocalyptic number.
255122140211431 is a deficient number, since it is larger than the sum of its proper divisors (1).
255122140211431 is an equidigital number, since it uses as much as digits as its factorization.
255122140211431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 255122140211431 its reverse (134112041221552), we get a palindrome (389234181432983).
The spelling of 255122140211431 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, four hundred thirty-one".
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