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255122140211431 is a prime number
BaseRepresentation
bin111010000000100001000000…
…100010101010100011100111
31020110022102211121021001202221
4322000201000202222203213
5231414410120343231211
62302333254312013211
7104510652315336013
oct7200410042524347
91213272747231687
10255122140211431
1174320768146599
1224744468691207
13ac47bb748a16c
1446ddd98273543
151e764a4232c71
hexe808408aa8e7

255122140211431 has 2 divisors, whose sum is σ = 255122140211432. Its totient is φ = 255122140211430.

The previous prime is 255122140211417. The next prime is 255122140211473. The reversal of 255122140211431 is 134112041221552.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255122140211431 is a prime.

It is a super-2 number, since 2×2551221402114312 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255122140211131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127561070105715 + 127561070105716.

It is an arithmetic number, because the mean of its divisors is an integer number (127561070105716).

Almost surely, 2255122140211431 is an apocalyptic number.

255122140211431 is a deficient number, since it is larger than the sum of its proper divisors (1).

255122140211431 is an equidigital number, since it uses as much as digits as its factorization.

255122140211431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19200, while the sum is 34.

Adding to 255122140211431 its reverse (134112041221552), we get a palindrome (389234181432983).

The spelling of 255122140211431 in words is "two hundred fifty-five trillion, one hundred twenty-two billion, one hundred forty million, two hundred eleven thousand, four hundred thirty-one".