25512437130 has 16 divisors (see below), whose sum is σ = 61229849184. Its totient is φ = 6803316560.

The previous prime is 25512437077. The next prime is 25512437201. The reversal of 25512437130 is 3173421552.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 25512437091 and 25512437100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 425207256 + ... + 425207315.

It is an arithmetic number, because the mean of its divisors is an integer number (3826865574).

Almost surely, 2^25512437130 is an apocalyptic number.

25512437130 is an abundant number, since it is smaller than the sum of its proper divisors (35717412054).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

25512437130 is a wasteful number, since it uses less digits than its factorization.

25512437130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 850414581.

The product of its (nonzero) digits is 25200, while the sum is 33.

Adding to 25512437130 its reverse (3173421552), we get a palindrome (28685858682).

The spelling of 25512437130 in words is "twenty-five billion, five hundred twelve million, four hundred thirty-seven thousand, one hundred thirty".