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255130009 is a prime number
BaseRepresentation
bin11110011010011…
…11100110011001
3122210001221120121
433031033212121
51010303130014
641152153241
76215366161
oct1715174631
9583057517
10255130009
11121017a52
1271538821
1340b1a704
1425c535a1
15175e9124
hexf34f999

255130009 has 2 divisors, whose sum is σ = 255130010. Its totient is φ = 255130008.

The previous prime is 255129997. The next prime is 255130027. The reversal of 255130009 is 900031552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 224160784 + 30969225 = 14972^2 + 5565^2 .

It is a cyclic number.

It is not a de Polignac number, because 255130009 - 213 = 255121817 is a prime.

It is not a weakly prime, because it can be changed into another prime (255130069) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127565004 + 127565005.

It is an arithmetic number, because the mean of its divisors is an integer number (127565005).

Almost surely, 2255130009 is an apocalyptic number.

It is an amenable number.

255130009 is a deficient number, since it is larger than the sum of its proper divisors (1).

255130009 is an equidigital number, since it uses as much as digits as its factorization.

255130009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 25.

The square root of 255130009 is about 15972.7896436408. The cubic root of 255130009 is about 634.2403207796.

The spelling of 255130009 in words is "two hundred fifty-five million, one hundred thirty thousand, nine".