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255135101843 is a prime number
BaseRepresentation
bin1110110110011100111…
…1001011001110010011
3220101112210201001120102
43231213033023032103
513140004041224333
6313112450403015
724301325404106
oct3554717131623
9811483631512
10255135101843
1199225128276
124154429046b
131b09cc014ab
14c4c480073d
156983a5aae8
hex3b673cb393

255135101843 has 2 divisors, whose sum is σ = 255135101844. Its totient is φ = 255135101842.

The previous prime is 255135101827. The next prime is 255135101911. The reversal of 255135101843 is 348101531552.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255135101843 - 24 = 255135101827 is a prime.

It is a super-3 number, since 3×2551351018433 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255135101797 and 255135101806.

It is not a weakly prime, because it can be changed into another prime (255135101803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127567550921 + 127567550922.

It is an arithmetic number, because the mean of its divisors is an integer number (127567550922).

Almost surely, 2255135101843 is an apocalyptic number.

255135101843 is a deficient number, since it is larger than the sum of its proper divisors (1).

255135101843 is an equidigital number, since it uses as much as digits as its factorization.

255135101843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 38.

Adding to 255135101843 its sum of digits (38), we get a square (255135101881 = 5051092).

The spelling of 255135101843 in words is "two hundred fifty-five billion, one hundred thirty-five million, one hundred one thousand, eight hundred forty-three".