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255152455049 is a prime number
BaseRepresentation
bin1110110110100001000…
…1010111110110001001
3220101121000100200200202
43231220101113312021
513140023012030144
6313114310341545
724301626040412
oct3555021276611
9811530320622
10255152455049
11992339aaa68
124154a05a8b5
131b0a3698c6b
14c4c6c3a809
15698533764e
hex3b68457d89

255152455049 has 2 divisors, whose sum is σ = 255152455050. Its totient is φ = 255152455048.

The previous prime is 255152455043. The next prime is 255152455073. The reversal of 255152455049 is 940554251552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 245651079424 + 9501375625 = 495632^2 + 97475^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255152455049 is a prime.

It is a super-3 number, since 3×2551524550493 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255152454994 and 255152455012.

It is not a weakly prime, because it can be changed into another prime (255152455043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127576227524 + 127576227525.

It is an arithmetic number, because the mean of its divisors is an integer number (127576227525).

Almost surely, 2255152455049 is an apocalyptic number.

It is an amenable number.

255152455049 is a deficient number, since it is larger than the sum of its proper divisors (1).

255152455049 is an equidigital number, since it uses as much as digits as its factorization.

255152455049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800000, while the sum is 47.

The spelling of 255152455049 in words is "two hundred fifty-five billion, one hundred fifty-two million, four hundred fifty-five thousand, forty-nine".