Base | Representation |
---|---|
bin | 100101001001001111010… |
… | …101100111101011011101 |
3 | 100001000120000102111102111 |
4 | 211021033111213223131 |
5 | 313310101130011222 |
6 | 5232342121554021 |
7 | 352262234651464 |
oct | 45111725475335 |
9 | 10030500374374 |
10 | 2552541641437 |
11 | 8a4588237147 |
12 | 352849045911 |
13 | 15691bba0cb8 |
14 | 8b787bb39db |
15 | 465e66a9777 |
hex | 2524f567add |
2552541641437 has 2 divisors, whose sum is σ = 2552541641438. Its totient is φ = 2552541641436.
The previous prime is 2552541641417. The next prime is 2552541641449. The reversal of 2552541641437 is 7341461452552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2098850485081 + 453691156356 = 1448741^2 + 673566^2 .
It is a cyclic number.
It is not a de Polignac number, because 2552541641437 - 231 = 2550394157789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2552541641407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276270820718 + 1276270820719.
It is an arithmetic number, because the mean of its divisors is an integer number (1276270820719).
Almost surely, 22552541641437 is an apocalyptic number.
It is an amenable number.
2552541641437 is a deficient number, since it is larger than the sum of its proper divisors (1).
2552541641437 is an equidigital number, since it uses as much as digits as its factorization.
2552541641437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4032000, while the sum is 49.
The spelling of 2552541641437 in words is "two trillion, five hundred fifty-two billion, five hundred forty-one million, six hundred forty-one thousand, four hundred thirty-seven".
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