Base | Representation |
---|---|
bin | 1011100111000001010101… |
… | …10000101000101011110011 |
3 | 10100101122101210201122222120 |
4 | 11303200222300220223303 |
5 | 11321240421232000201 |
6 | 130144153234205323 |
7 | 5243324162655654 |
oct | 563405260505363 |
9 | 110348353648876 |
10 | 25530003000051 |
11 | 8153239145000 |
12 | 2a43a76423843 |
13 | 113261339b524 |
14 | 64393181352b |
15 | 2e4162208536 |
hex | 17382ac28af3 |
25530003000051 has 32 divisors (see below), whose sum is σ = 39069336061440. Its totient is φ = 14800001685920.
The previous prime is 25530002999971. The next prime is 25530003000079. The reversal of 25530003000051 is 15000030003552.
It is not a de Polignac number, because 25530003000051 - 237 = 25392564046579 is a prime.
It is a super-2 number, since 2×255300030000512 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 25530002999985 and 25530003000030.
It is not an unprimeable number, because it can be changed into a prime (25530003100051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 138901416 + ... + 139085093.
It is an arithmetic number, because the mean of its divisors is an integer number (1220916751920).
Almost surely, 225530003000051 is an apocalyptic number.
25530003000051 is a deficient number, since it is larger than the sum of its proper divisors (13539333061389).
25530003000051 is a wasteful number, since it uses less digits than its factorization.
25530003000051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 277986568 (or 277986546 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 24.
The spelling of 25530003000051 in words is "twenty-five trillion, five hundred thirty billion, three million, fifty-one", and thus it is an aban number.
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