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25530006902431 is a prime number
BaseRepresentation
bin1011100111000001010101…
…11111100001011010011111
310100101122102002001221001011
411303200222333201122133
511321240423231334211
6130144153454000051
75243324241101113
oct563405277413237
9110348362057034
1025530006902431
11815324036aa09
122a43a777a6027
131132614136825
1464393214b743
152e4162729921
hex17382afe169f

25530006902431 has 2 divisors, whose sum is σ = 25530006902432. Its totient is φ = 25530006902430.

The previous prime is 25530006902341. The next prime is 25530006902437. The reversal of 25530006902431 is 13420960003552.

Together with previous prime (25530006902341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25530006902431 - 227 = 25529872684703 is a prime.

It is a super-2 number, since 2×255300069024312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25530006902437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12765003451215 + 12765003451216.

It is an arithmetic number, because the mean of its divisors is an integer number (12765003451216).

Almost surely, 225530006902431 is an apocalyptic number.

25530006902431 is a deficient number, since it is larger than the sum of its proper divisors (1).

25530006902431 is an equidigital number, since it uses as much as digits as its factorization.

25530006902431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 40.

Adding to 25530006902431 its reverse (13420960003552), we get a palindrome (38950966905983).

The spelling of 25530006902431 in words is "twenty-five trillion, five hundred thirty billion, six million, nine hundred two thousand, four hundred thirty-one".