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2553100107 = 3851033369
BaseRepresentation
bin1001100000101101…
…0011011101001011
320120221002220221020
42120023103131023
520212043200412
61101201443523
7120160664355
oct23013233513
96527086836
102553100107
1110a0181998
125b30405a3
13318c3192c
141a31140d5
15ee21918c
hex982d374b

2553100107 has 4 divisors (see below), whose sum is σ = 3404133480. Its totient is φ = 1702066736.

The previous prime is 2553100093. The next prime is 2553100111. The reversal of 2553100107 is 7010013552.

2553100107 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2553100107 - 28 = 2553099851 is a prime.

It is a super-2 number, since 2×25531001072 = 13036640312726822898, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2553100127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425516682 + ... + 425516687.

It is an arithmetic number, because the mean of its divisors is an integer number (851033370).

Almost surely, 22553100107 is an apocalyptic number.

2553100107 is a deficient number, since it is larger than the sum of its proper divisors (851033373).

2553100107 is an equidigital number, since it uses as much as digits as its factorization.

2553100107 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 851033372.

The product of its (nonzero) digits is 1050, while the sum is 24.

The square root of 2553100107 is about 50528.2110013802. The cubic root of 2553100107 is about 1366.7506253464.

Adding to 2553100107 its reverse (7010013552), we get a palindrome (9563113659).

The spelling of 2553100107 in words is "two billion, five hundred fifty-three million, one hundred thousand, one hundred seven".

Divisors: 1 3 851033369 2553100107