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2553100127 is a prime number
BaseRepresentation
bin1001100000101101…
…0011011101011111
320120221002220221222
42120023103131133
520212043201002
61101201443555
7120160664414
oct23013233537
96527086858
102553100127
1110a0181a06
125b30405bb
13318c31946
141a311410b
15ee2191a2
hex982d375f

2553100127 has 2 divisors, whose sum is σ = 2553100128. Its totient is φ = 2553100126.

The previous prime is 2553100111. The next prime is 2553100141. The reversal of 2553100127 is 7210013552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2553100127 - 24 = 2553100111 is a prime.

It is a super-2 number, since 2×25531001272 = 13036640516974832258, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2553100096 and 2553100105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2553100427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276550063 + 1276550064.

It is an arithmetic number, because the mean of its divisors is an integer number (1276550064).

Almost surely, 22553100127 is an apocalyptic number.

2553100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

2553100127 is an equidigital number, since it uses as much as digits as its factorization.

2553100127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2100, while the sum is 26.

The square root of 2553100127 is about 50528.2111992895. The cubic root of 2553100127 is about 1366.7506289152.

Adding to 2553100127 its reverse (7210013552), we get a palindrome (9763113679).

The spelling of 2553100127 in words is "two billion, five hundred fifty-three million, one hundred thousand, one hundred twenty-seven".