Base | Representation |
---|---|
bin | 1001100000101101… |
… | …0011011101001111 |
3 | 20120221002220221101 |
4 | 2120023103131033 |
5 | 20212043200421 |
6 | 1101201443531 |
7 | 120160664362 |
oct | 23013233517 |
9 | 6527086841 |
10 | 2553100111 |
11 | 10a01819a1 |
12 | 5b30405a7 |
13 | 318c31933 |
14 | 1a31140d9 |
15 | ee219191 |
hex | 982d374f |
2553100111 has 2 divisors, whose sum is σ = 2553100112. Its totient is φ = 2553100110.
The previous prime is 2553100093. The next prime is 2553100127. The reversal of 2553100111 is 1110013552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2553100111 - 29 = 2553099599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2553100141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276550055 + 1276550056.
It is an arithmetic number, because the mean of its divisors is an integer number (1276550056).
Almost surely, 22553100111 is an apocalyptic number.
2553100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
2553100111 is an equidigital number, since it uses as much as digits as its factorization.
2553100111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 150, while the sum is 19.
The square root of 2553100111 is about 50528.2110409621. The cubic root of 2553100111 is about 1366.7506260601.
Adding to 2553100111 its reverse (1110013552), we get a palindrome (3663113663).
The spelling of 2553100111 in words is "two billion, five hundred fifty-three million, one hundred thousand, one hundred eleven".
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