Base | Representation |
---|---|
bin | 1110110111001110000… |
… | …0101010000001011001 |
3 | 220102002011011022212201 |
4 | 3231303200222001121 |
5 | 13140414244323113 |
6 | 313145124010201 |
7 | 24306405532333 |
oct | 3556340520131 |
9 | 812064138781 |
10 | 255341011033 |
11 | 99320386959 |
12 | 415a1230961 |
13 | 1b103777354 |
14 | c503cc0453 |
15 | 6996b80cdd |
hex | 3b7382a059 |
255341011033 has 2 divisors, whose sum is σ = 255341011034. Its totient is φ = 255341011032.
The previous prime is 255341011027. The next prime is 255341011069. The reversal of 255341011033 is 330110143552.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 254850299929 + 490711104 = 504827^2 + 22152^2 .
It is a cyclic number.
It is not a de Polignac number, because 255341011033 - 221 = 255338913881 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255341010992 and 255341011010.
It is not a weakly prime, because it can be changed into another prime (255341018033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127670505516 + 127670505517.
It is an arithmetic number, because the mean of its divisors is an integer number (127670505517).
Almost surely, 2255341011033 is an apocalyptic number.
It is an amenable number.
255341011033 is a deficient number, since it is larger than the sum of its proper divisors (1).
255341011033 is an equidigital number, since it uses as much as digits as its factorization.
255341011033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 255341011033 its reverse (330110143552), we get a palindrome (585451154585).
The spelling of 255341011033 in words is "two hundred fifty-five billion, three hundred forty-one million, eleven thousand, thirty-three".
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