Base | Representation |
---|---|
bin | 11110011100000… |
… | …11001001010001 |
3 | 122210110200012011 |
4 | 33032003021101 |
5 | 1010331404022 |
6 | 41200502521 |
7 | 6220235542 |
oct | 1716031121 |
9 | 583420164 |
10 | 255341137 |
11 | 121151637 |
12 | 7161aa41 |
13 | 40b9283c |
14 | 25caa4c9 |
15 | 1763b977 |
hex | f383251 |
255341137 has 2 divisors, whose sum is σ = 255341138. Its totient is φ = 255341136.
The previous prime is 255341081. The next prime is 255341179. The reversal of 255341137 is 731143552.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 164634561 + 90706576 = 12831^2 + 9524^2 .
It is a cyclic number.
It is not a de Polignac number, because 255341137 - 215 = 255308369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 255341099 and 255341108.
It is not a weakly prime, because it can be changed into another prime (255341197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127670568 + 127670569.
It is an arithmetic number, because the mean of its divisors is an integer number (127670569).
Almost surely, 2255341137 is an apocalyptic number.
It is an amenable number.
255341137 is a deficient number, since it is larger than the sum of its proper divisors (1).
255341137 is an equidigital number, since it uses as much as digits as its factorization.
255341137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12600, while the sum is 31.
The square root of 255341137 is about 15979.3972664804. The cubic root of 255341137 is about 634.4152237253.
Adding to 255341137 its reverse (731143552), we get a palindrome (986484689).
The spelling of 255341137 in words is "two hundred fifty-five million, three hundred forty-one thousand, one hundred thirty-seven".
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