Base | Representation |
---|---|
bin | 1110110111010110011… |
… | …1000011110000011101 |
3 | 220102011121110100001211 |
4 | 3231311213003300131 |
5 | 13141002304244431 |
6 | 313152423104421 |
7 | 24310314153523 |
oct | 3556547036035 |
9 | 812147410054 |
10 | 255376243741 |
11 | 993392607a3 |
12 | 415b0ba2111 |
13 | 1b10ab61cc8 |
14 | c508852313 |
15 | 6999ce02b1 |
hex | 3b759c3c1d |
255376243741 has 2 divisors, whose sum is σ = 255376243742. Its totient is φ = 255376243740.
The previous prime is 255376243699. The next prime is 255376243763. The reversal of 255376243741 is 147342673552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 170386502841 + 84989740900 = 412779^2 + 291530^2 .
It is a cyclic number.
It is not a de Polignac number, because 255376243741 - 213 = 255376235549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255376243141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127688121870 + 127688121871.
It is an arithmetic number, because the mean of its divisors is an integer number (127688121871).
Almost surely, 2255376243741 is an apocalyptic number.
It is an amenable number.
255376243741 is a deficient number, since it is larger than the sum of its proper divisors (1).
255376243741 is an equidigital number, since it uses as much as digits as its factorization.
255376243741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4233600, while the sum is 49.
The spelling of 255376243741 in words is "two hundred fifty-five billion, three hundred seventy-six million, two hundred forty-three thousand, seven hundred forty-one".
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