Base | Representation |
---|---|
bin | 1011100111010001100101… |
… | …11101000100010000000101 |
3 | 10100102110221000220002010121 |
4 | 11303220302331010100011 |
5 | 11321411304441123023 |
6 | 130152155241021541 |
7 | 5244053355513541 |
oct | 563506275042005 |
9 | 110373830802117 |
10 | 25538730411013 |
11 | 8156a07584036 |
12 | 2a456b11848b1 |
13 | 11333a452a421 |
14 | 64411c94ca21 |
15 | 2e44c34dcd5d |
hex | 173a32f44405 |
25538730411013 has 2 divisors, whose sum is σ = 25538730411014. Its totient is φ = 25538730411012.
The previous prime is 25538730410993. The next prime is 25538730411059. The reversal of 25538730411013 is 31011403783552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24129148852449 + 1409581558564 = 4912143^2 + 1187258^2 .
It is a cyclic number.
It is not a de Polignac number, because 25538730411013 - 217 = 25538730279941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25538730411613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12769365205506 + 12769365205507.
It is an arithmetic number, because the mean of its divisors is an integer number (12769365205507).
Almost surely, 225538730411013 is an apocalyptic number.
It is an amenable number.
25538730411013 is a deficient number, since it is larger than the sum of its proper divisors (1).
25538730411013 is an equidigital number, since it uses as much as digits as its factorization.
25538730411013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 43.
The spelling of 25538730411013 in words is "twenty-five trillion, five hundred thirty-eight billion, seven hundred thirty million, four hundred eleven thousand, thirteen".
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