Base | Representation |
---|---|
bin | 1001100000111010… |
… | …1100000010110101 |
3 | 20120222202222212111 |
4 | 2120032230002311 |
5 | 20212310043003 |
6 | 1101232451021 |
7 | 120201350656 |
oct | 23016540265 |
9 | 6528688774 |
10 | 2553987253 |
11 | 10a0728474 |
12 | 5b33a9a71 |
13 | 31918267c |
14 | 1a32a552d |
15 | ee341e6d |
hex | 983ac0b5 |
2553987253 has 2 divisors, whose sum is σ = 2553987254. Its totient is φ = 2553987252.
The previous prime is 2553987203. The next prime is 2553987257. The reversal of 2553987253 is 3527893552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2426252049 + 127735204 = 49257^2 + 11302^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2553987253 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2553987197 and 2553987206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2553987257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1276993626 + 1276993627.
It is an arithmetic number, because the mean of its divisors is an integer number (1276993627).
Almost surely, 22553987253 is an apocalyptic number.
It is an amenable number.
2553987253 is a deficient number, since it is larger than the sum of its proper divisors (1).
2553987253 is an equidigital number, since it uses as much as digits as its factorization.
2553987253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2268000, while the sum is 49.
The square root of 2553987253 is about 50536.9889585836. The cubic root of 2553987253 is about 1366.9089122508.
The spelling of 2553987253 in words is "two billion, five hundred fifty-three million, nine hundred eighty-seven thousand, two hundred fifty-three".
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