Base | Representation |
---|---|
bin | 1110110111011100100… |
… | …1110001100011011001 |
3 | 220102020102011001120212 |
4 | 3231313021301203121 |
5 | 13141030420341213 |
6 | 313155145500505 |
7 | 24311050132634 |
oct | 3556711614331 |
9 | 812212131525 |
10 | 255402121433 |
11 | 99351926018 |
12 | 415b97a1735 |
13 | 1b113322854 |
14 | c50c06ac1b |
15 | 699c2029a8 |
hex | 3b772718d9 |
255402121433 has 2 divisors, whose sum is σ = 255402121434. Its totient is φ = 255402121432.
The previous prime is 255402121409. The next prime is 255402121453. The reversal of 255402121433 is 334121204552.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 252799795264 + 2602326169 = 502792^2 + 51013^2 .
It is a cyclic number.
It is not a de Polignac number, because 255402121433 - 216 = 255402055897 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 255402121433.
It is not a weakly prime, because it can be changed into another prime (255402121453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127701060716 + 127701060717.
It is an arithmetic number, because the mean of its divisors is an integer number (127701060717).
Almost surely, 2255402121433 is an apocalyptic number.
It is an amenable number.
255402121433 is a deficient number, since it is larger than the sum of its proper divisors (1).
255402121433 is an equidigital number, since it uses as much as digits as its factorization.
255402121433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 255402121433 its reverse (334121204552), we get a palindrome (589523325985).
The spelling of 255402121433 in words is "two hundred fifty-five billion, four hundred two million, one hundred twenty-one thousand, four hundred thirty-three".
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