Base | Representation |
---|---|
bin | 1011100111010100010111… |
… | …11100011010011100100111 |
3 | 10100102121210002020101110201 |
4 | 11303222023330122130213 |
5 | 11321422334143141012 |
6 | 130153003333131331 |
7 | 5244135355021243 |
oct | 563521374323447 |
9 | 110377702211421 |
10 | 25540223412007 |
11 | 8157603313857 |
12 | 2a45a49189b47 |
13 | 113358193ba75 |
14 | 644220d4d423 |
15 | 2e455e603857 |
hex | 173a8bf1a727 |
25540223412007 has 2 divisors, whose sum is σ = 25540223412008. Its totient is φ = 25540223412006.
The previous prime is 25540223411993. The next prime is 25540223412061. The reversal of 25540223412007 is 70021432204552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25540223412007 - 211 = 25540223409959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25540223412097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12770111706003 + 12770111706004.
It is an arithmetic number, because the mean of its divisors is an integer number (12770111706004).
Almost surely, 225540223412007 is an apocalyptic number.
25540223412007 is a deficient number, since it is larger than the sum of its proper divisors (1).
25540223412007 is an equidigital number, since it uses as much as digits as its factorization.
25540223412007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 37.
Adding to 25540223412007 its reverse (70021432204552), we get a palindrome (95561655616559).
The spelling of 25540223412007 in words is "twenty-five trillion, five hundred forty billion, two hundred twenty-three million, four hundred twelve thousand, seven".
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