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2554037305493 is a prime number
BaseRepresentation
bin100101001010101000011…
…111001000000010010101
3100001011102020210002210112
4211022220133020002111
5313321132022233433
65233150351132405
7352344265620212
oct45125037100225
910034366702715
102554037305493
118a5185525743
12352ba5b14105
13156ac9a0580b
148b88a6a8b09
1546682b49348
hex252a87c8095

2554037305493 has 2 divisors, whose sum is σ = 2554037305494. Its totient is φ = 2554037305492.

The previous prime is 2554037305441. The next prime is 2554037305507. The reversal of 2554037305493 is 3945037304552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1315753525969 + 1238283779524 = 1147063^2 + 1112782^2 .

It is a cyclic number.

It is not a de Polignac number, because 2554037305493 - 226 = 2553970196629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2554037305433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277018652746 + 1277018652747.

It is an arithmetic number, because the mean of its divisors is an integer number (1277018652747).

Almost surely, 22554037305493 is an apocalyptic number.

It is an amenable number.

2554037305493 is a deficient number, since it is larger than the sum of its proper divisors (1).

2554037305493 is an equidigital number, since it uses as much as digits as its factorization.

2554037305493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804000, while the sum is 50.

The spelling of 2554037305493 in words is "two trillion, five hundred fifty-four billion, thirty-seven million, three hundred five thousand, four hundred ninety-three".