Base | Representation |
---|---|
bin | 100101001010101000011… |
… | …111001000000010111011 |
3 | 100001011102020210002211221 |
4 | 211022220133020002323 |
5 | 313321132022234111 |
6 | 5233150351132511 |
7 | 352344265620265 |
oct | 45125037100273 |
9 | 10034366702757 |
10 | 2554037305531 |
11 | 8a5185525778 |
12 | 352ba5b14137 |
13 | 156ac9a0583a |
14 | 8b88a6a8b35 |
15 | 46682b49371 |
hex | 252a87c80bb |
2554037305531 has 2 divisors, whose sum is σ = 2554037305532. Its totient is φ = 2554037305530.
The previous prime is 2554037305529. The next prime is 2554037305591. The reversal of 2554037305531 is 1355037304552.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2554037305531 - 21 = 2554037305529 is a prime.
It is a super-2 number, since 2×25540373055312 (a number of 26 digits) contains 22 as substring.
Together with 2554037305529, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (2554037305591) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277018652765 + 1277018652766.
It is an arithmetic number, because the mean of its divisors is an integer number (1277018652766).
Almost surely, 22554037305531 is an apocalyptic number.
2554037305531 is a deficient number, since it is larger than the sum of its proper divisors (1).
2554037305531 is an equidigital number, since it uses as much as digits as its factorization.
2554037305531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 945000, while the sum is 43.
The spelling of 2554037305531 in words is "two trillion, five hundred fifty-four billion, thirty-seven million, three hundred five thousand, five hundred thirty-one".
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