Base | Representation |
---|---|
bin | 111010000100110111100001… |
… | …111101011101010100110011 |
3 | 1020111101000202200002210222112 |
4 | 322010313201331131110303 |
5 | 231434310104441012243 |
6 | 2303122514020555535 |
7 | 104541400321130303 |
oct | 7204674175352463 |
9 | 1214330680083875 |
10 | 255421201110323 |
11 | 74426583234276 |
12 | 2479240b552bab |
13 | ac6a167881a31 |
14 | 471064879b603 |
15 | 1e7e15923e818 |
hex | e84de1f5d533 |
255421201110323 has 2 divisors, whose sum is σ = 255421201110324. Its totient is φ = 255421201110322.
The previous prime is 255421201110217. The next prime is 255421201110337. The reversal of 255421201110323 is 323011102124552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255421201110323 - 28 = 255421201110067 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 255421201110323.
It is not a weakly prime, because it can be changed into another prime (255421201110343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127710600555161 + 127710600555162.
It is an arithmetic number, because the mean of its divisors is an integer number (127710600555162).
Almost surely, 2255421201110323 is an apocalyptic number.
255421201110323 is a deficient number, since it is larger than the sum of its proper divisors (1).
255421201110323 is an equidigital number, since it uses as much as digits as its factorization.
255421201110323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 255421201110323 its reverse (323011102124552), we get a palindrome (578432303234875).
The spelling of 255421201110323 in words is "two hundred fifty-five trillion, four hundred twenty-one billion, two hundred one million, one hundred ten thousand, three hundred twenty-three".
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