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255430121431 is a prime number
BaseRepresentation
bin1110110111100011010…
…0100101011111010111
3220102022100211121100211
43231320310211133113
513141110102341211
6313202025550251
724311540131402
oct3557064453727
9812270747324
10255430121431
119936670a911
1241607045387
131b1190773b4
14c511a78d39
15699e8d3e21
hex3b78d257d7

255430121431 has 2 divisors, whose sum is σ = 255430121432. Its totient is φ = 255430121430.

The previous prime is 255430121377. The next prime is 255430121449. The reversal of 255430121431 is 134121034552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255430121431 - 217 = 255429990359 is a prime.

It is a super-2 number, since 2×2554301214312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255430121393 and 255430121402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255430121831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127715060715 + 127715060716.

It is an arithmetic number, because the mean of its divisors is an integer number (127715060716).

Almost surely, 2255430121431 is an apocalyptic number.

255430121431 is a deficient number, since it is larger than the sum of its proper divisors (1).

255430121431 is an equidigital number, since it uses as much as digits as its factorization.

255430121431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 255430121431 its reverse (134121034552), we get a palindrome (389551155983).

The spelling of 255430121431 in words is "two hundred fifty-five billion, four hundred thirty million, one hundred twenty-one thousand, four hundred thirty-one".