Base | Representation |
---|---|
bin | 1110110111100011010… |
… | …0100101011111010111 |
3 | 220102022100211121100211 |
4 | 3231320310211133113 |
5 | 13141110102341211 |
6 | 313202025550251 |
7 | 24311540131402 |
oct | 3557064453727 |
9 | 812270747324 |
10 | 255430121431 |
11 | 9936670a911 |
12 | 41607045387 |
13 | 1b1190773b4 |
14 | c511a78d39 |
15 | 699e8d3e21 |
hex | 3b78d257d7 |
255430121431 has 2 divisors, whose sum is σ = 255430121432. Its totient is φ = 255430121430.
The previous prime is 255430121377. The next prime is 255430121449. The reversal of 255430121431 is 134121034552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 255430121431 - 217 = 255429990359 is a prime.
It is a super-2 number, since 2×2554301214312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 255430121393 and 255430121402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255430121831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127715060715 + 127715060716.
It is an arithmetic number, because the mean of its divisors is an integer number (127715060716).
Almost surely, 2255430121431 is an apocalyptic number.
255430121431 is a deficient number, since it is larger than the sum of its proper divisors (1).
255430121431 is an equidigital number, since it uses as much as digits as its factorization.
255430121431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 255430121431 its reverse (134121034552), we get a palindrome (389551155983).
The spelling of 255430121431 in words is "two hundred fifty-five billion, four hundred thirty million, one hundred twenty-one thousand, four hundred thirty-one".
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