Base | Representation |
---|---|
bin | 1110110111100101010… |
… | …1110011011000111101 |
3 | 220102022222020000001201 |
4 | 3231321111303120331 |
5 | 13141114320012432 |
6 | 313202540335501 |
7 | 24312004136263 |
oct | 3557125633075 |
9 | 812288200051 |
10 | 255438829117 |
11 | 9937061804a |
12 | 41609b44591 |
13 | 1b11ab05984 |
14 | c512ca4433 |
15 | 69a0553ee7 |
hex | 3b7957363d |
255438829117 has 2 divisors, whose sum is σ = 255438829118. Its totient is φ = 255438829116.
The previous prime is 255438829073. The next prime is 255438829169. The reversal of 255438829117 is 711928834552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 251864463321 + 3574365796 = 501861^2 + 59786^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255438829117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (255438829187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127719414558 + 127719414559.
It is an arithmetic number, because the mean of its divisors is an integer number (127719414559).
Almost surely, 2255438829117 is an apocalyptic number.
It is an amenable number.
255438829117 is a deficient number, since it is larger than the sum of its proper divisors (1).
255438829117 is an equidigital number, since it uses as much as digits as its factorization.
255438829117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4838400, while the sum is 55.
The spelling of 255438829117 in words is "two hundred fifty-five billion, four hundred thirty-eight million, eight hundred twenty-nine thousand, one hundred seventeen".
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