Base | Representation |
---|---|
bin | 111010000101001010010001… |
… | …001001011100100101100111 |
3 | 1020111102221200210121011102012 |
4 | 322011022101021130211213 |
5 | 231440122310423310030 |
6 | 2303140042241304435 |
7 | 104543012020044050 |
oct | 7205122111344547 |
9 | 1214387623534365 |
10 | 255441320135015 |
11 | 74434067969303 |
12 | 247962a533511b |
13 | ac6c022b01681 |
14 | 47115d67c7727 |
15 | 1e7e93566c095 |
hex | e8529125c967 |
255441320135015 has 32 divisors (see below), whose sum is σ = 356102423255040. Its totient is φ = 172290469837824.
The previous prime is 255441320135011. The next prime is 255441320135017. The reversal of 255441320135015 is 510531023144552.
It is a cyclic number.
It is not a de Polignac number, because 255441320135015 - 22 = 255441320135011 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (255441320135011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 230245535 + ... + 231352304.
It is an arithmetic number, because the mean of its divisors is an integer number (11128200726720).
Almost surely, 2255441320135015 is an apocalyptic number.
255441320135015 is a deficient number, since it is larger than the sum of its proper divisors (100661103120025).
255441320135015 is a wasteful number, since it uses less digits than its factorization.
255441320135015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 461598111.
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 255441320135015 its reverse (510531023144552), we get a palindrome (765972343279567).
The spelling of 255441320135015 in words is "two hundred fifty-five trillion, four hundred forty-one billion, three hundred twenty million, one hundred thirty-five thousand, fifteen".
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