Base | Representation |
---|---|
bin | 100101001011101010110… |
… | …101001111101110010011 |
3 | 100001021021211021011221221 |
4 | 211023222311033232103 |
5 | 313330422000303103 |
6 | 5233453032425511 |
7 | 352414003022656 |
oct | 45135265175623 |
9 | 10037254234857 |
10 | 2555150400403 |
11 | 8a56a6874397 |
12 | 353256848297 |
13 | 156c464bc963 |
14 | 8b95445589d |
15 | 466ea71a1bd |
hex | 252ead4fb93 |
2555150400403 has 2 divisors, whose sum is σ = 2555150400404. Its totient is φ = 2555150400402.
The previous prime is 2555150400371. The next prime is 2555150400419. The reversal of 2555150400403 is 3040040515552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2555150400403 - 25 = 2555150400371 is a prime.
It is a super-2 number, since 2×25551504004032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2555150470403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277575200201 + 1277575200202.
It is an arithmetic number, because the mean of its divisors is an integer number (1277575200202).
Almost surely, 22555150400403 is an apocalyptic number.
2555150400403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2555150400403 is an equidigital number, since it uses as much as digits as its factorization.
2555150400403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60000, while the sum is 34.
Adding to 2555150400403 its reverse (3040040515552), we get a palindrome (5595190915955).
The spelling of 2555150400403 in words is "two trillion, five hundred fifty-five billion, one hundred fifty million, four hundred thousand, four hundred three".
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