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2555231413901 is a prime number
BaseRepresentation
bin100101001011101111101…
…010010010011010001101
3100001021111110201002120212
4211023233222102122031
5313331103220221101
65233505045052205
7352416005436635
oct45135752223215
910037443632525
102555231413901
118a5738577aa1
123532799b7065
13156c5a21643a
148b9611036c5
15467028be1bb
hex252efa9268d

2555231413901 has 2 divisors, whose sum is σ = 2555231413902. Its totient is φ = 2555231413900.

The previous prime is 2555231413879. The next prime is 2555231413949. The reversal of 2555231413901 is 1093141325552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2358405204100 + 196826209801 = 1535710^2 + 443651^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2555231413901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2555231413951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277615706950 + 1277615706951.

It is an arithmetic number, because the mean of its divisors is an integer number (1277615706951).

Almost surely, 22555231413901 is an apocalyptic number.

It is an amenable number.

2555231413901 is a deficient number, since it is larger than the sum of its proper divisors (1).

2555231413901 is an equidigital number, since it uses as much as digits as its factorization.

2555231413901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 41.

The spelling of 2555231413901 in words is "two trillion, five hundred fifty-five billion, two hundred thirty-one million, four hundred thirteen thousand, nine hundred one".