Base | Representation |
---|---|
bin | 1110110111111111111… |
… | …0011001001110011011 |
3 | 220102121201122211111012 |
4 | 3231333332121032123 |
5 | 13141331313230042 |
6 | 313221554124135 |
7 | 24314525201651 |
oct | 3557776311633 |
9 | 812551584435 |
10 | 255550133147 |
11 | 9941842a451 |
12 | 4163b28064b |
13 | 1b137ba674a |
14 | c523998dd1 |
15 | 69aa1dce82 |
hex | 3b7ff9939b |
255550133147 has 2 divisors, whose sum is σ = 255550133148. Its totient is φ = 255550133146.
The previous prime is 255550133117. The next prime is 255550133159. The reversal of 255550133147 is 741331055552.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-255550133147 is a prime.
It is not a weakly prime, because it can be changed into another prime (255550133117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127775066573 + 127775066574.
It is an arithmetic number, because the mean of its divisors is an integer number (127775066574).
Almost surely, 2255550133147 is an apocalyptic number.
255550133147 is a deficient number, since it is larger than the sum of its proper divisors (1).
255550133147 is an equidigital number, since it uses as much as digits as its factorization.
255550133147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 315000, while the sum is 41.
Adding to 255550133147 its reverse (741331055552), we get a palindrome (996881188699).
The spelling of 255550133147 in words is "two hundred fifty-five billion, five hundred fifty million, one hundred thirty-three thousand, one hundred forty-seven".
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