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255550133117 is a prime number
BaseRepresentation
bin1110110111111111111…
…0011001001101111101
3220102121201122211110002
43231333332121031331
513141331313224432
6313221554124045
724314525201606
oct3557776311575
9812551584402
10255550133117
119941842a424
124163b280625
131b137ba6726
14c523998dad
1569aa1dce62
hex3b7ff9937d

255550133117 has 2 divisors, whose sum is σ = 255550133118. Its totient is φ = 255550133116.

The previous prime is 255550133101. The next prime is 255550133147. The reversal of 255550133117 is 711331055552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 255367504921 + 182628196 = 505339^2 + 13514^2 .

It is a cyclic number.

It is not a de Polignac number, because 255550133117 - 24 = 255550133101 is a prime.

It is a super-2 number, since 2×2555501331172 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255550133147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127775066558 + 127775066559.

It is an arithmetic number, because the mean of its divisors is an integer number (127775066559).

Almost surely, 2255550133117 is an apocalyptic number.

It is an amenable number.

255550133117 is a deficient number, since it is larger than the sum of its proper divisors (1).

255550133117 is an equidigital number, since it uses as much as digits as its factorization.

255550133117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78750, while the sum is 38.

Adding to 255550133117 its reverse (711331055552), we get a palindrome (966881188669).

The spelling of 255550133117 in words is "two hundred fifty-five billion, five hundred fifty million, one hundred thirty-three thousand, one hundred seventeen".