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25555345171141 is a prime number
BaseRepresentation
bin1011100111110000100010…
…10001010110001011000101
310100111001210221111100021211
411303320101101112023011
511322144321330434031
6130203544041011421
75245212163606462
oct563702121261305
9110431727440254
1025555345171141
118162a63139255
122a48969483b71
131134b21779636
14644c573ca669
152e4b46e69bb1
hex173e114562c5

25555345171141 has 2 divisors, whose sum is σ = 25555345171142. Its totient is φ = 25555345171140.

The previous prime is 25555345171079. The next prime is 25555345171159. The reversal of 25555345171141 is 14117154355552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19865927608641 + 5689417562500 = 4457121^2 + 2385250^2 .

It is a cyclic number.

It is not a de Polignac number, because 25555345171141 - 223 = 25555336782533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25555345171441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12777672585570 + 12777672585571.

It is an arithmetic number, because the mean of its divisors is an integer number (12777672585571).

Almost surely, 225555345171141 is an apocalyptic number.

It is an amenable number.

25555345171141 is a deficient number, since it is larger than the sum of its proper divisors (1).

25555345171141 is an equidigital number, since it uses as much as digits as its factorization.

25555345171141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2100000, while the sum is 49.

The spelling of 25555345171141 in words is "twenty-five trillion, five hundred fifty-five billion, three hundred forty-five million, one hundred seventy-one thousand, one hundred forty-one".