Base | Representation |
---|---|
bin | 100101001100000010010… |
… | …011111100100011011101 |
3 | 100001022022021111120222112 |
4 | 211030002103330203131 |
5 | 313332223321334232 |
6 | 5234000103523405 |
7 | 352426525230125 |
oct | 45140223744335 |
9 | 10038267446875 |
10 | 2555544324317 |
11 | 8a588916a246 |
12 | 353346759565 |
13 | 156ca9cb472a |
14 | 8b9908b7c85 |
15 | 467200cd4b2 |
hex | 253024fc8dd |
2555544324317 has 2 divisors, whose sum is σ = 2555544324318. Its totient is φ = 2555544324316.
The previous prime is 2555544324299. The next prime is 2555544324337. The reversal of 2555544324317 is 7134234455552.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2000204889796 + 555339434521 = 1414286^2 + 745211^2 .
It is a cyclic number.
It is not a de Polignac number, because 2555544324317 - 28 = 2555544324061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2555544324337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1277772162158 + 1277772162159.
It is an arithmetic number, because the mean of its divisors is an integer number (1277772162159).
Almost surely, 22555544324317 is an apocalyptic number.
It is an amenable number.
2555544324317 is a deficient number, since it is larger than the sum of its proper divisors (1).
2555544324317 is an equidigital number, since it uses as much as digits as its factorization.
2555544324317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10080000, while the sum is 50.
Adding to 2555544324317 its reverse (7134234455552), we get a palindrome (9689778779869).
The spelling of 2555544324317 in words is "two trillion, five hundred fifty-five billion, five hundred forty-four million, three hundred twenty-four thousand, three hundred seventeen".
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