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255602131 is a prime number
BaseRepresentation
bin11110011110000…
…10110111010011
3122210221221012121
433033002313103
51010413232011
641210235111
76222403501
oct1717026723
9583857177
10255602131
1112130a734
1271725a97
1340c54585
1425d37671
151768de71
hexf3c2dd3

255602131 has 2 divisors, whose sum is σ = 255602132. Its totient is φ = 255602130.

The previous prime is 255602071. The next prime is 255602141. The reversal of 255602131 is 131206552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255602131 - 217 = 255471059 is a prime.

It is a super-2 number, since 2×2556021312 = 130664898743482322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 255602096 and 255602105.

It is not a weakly prime, because it can be changed into another prime (255602141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127801065 + 127801066.

It is an arithmetic number, because the mean of its divisors is an integer number (127801066).

Almost surely, 2255602131 is an apocalyptic number.

255602131 is a deficient number, since it is larger than the sum of its proper divisors (1).

255602131 is an equidigital number, since it uses as much as digits as its factorization.

255602131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

The square root of 255602131 is about 15987.5617590676. The cubic root of 255602131 is about 634.6313035236.

Adding to 255602131 its reverse (131206552), we get a palindrome (386808683).

The spelling of 255602131 in words is "two hundred fifty-five million, six hundred two thousand, one hundred thirty-one".