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255612231253 is a prime number
BaseRepresentation
bin1110111000001110101…
…1010001111001010101
3220102210001111202002001
43232003223101321111
513141443212400003
6313232053115301
724316211055001
oct3560353217125
9812701452061
10255612231253
119944a4936a5
1241658028b31
131b147a096a2
14c52bd21701
1569b08a761d
hex3b83ad1e55

255612231253 has 2 divisors, whose sum is σ = 255612231254. Its totient is φ = 255612231252.

The previous prime is 255612231247. The next prime is 255612231307. The reversal of 255612231253 is 352132216552.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 249742066564 + 5870164689 = 499742^2 + 76617^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-255612231253 is a prime.

It is a super-2 number, since 2×2556122312532 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255612231223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127806115626 + 127806115627.

It is an arithmetic number, because the mean of its divisors is an integer number (127806115627).

Almost surely, 2255612231253 is an apocalyptic number.

It is an amenable number.

255612231253 is a deficient number, since it is larger than the sum of its proper divisors (1).

255612231253 is an equidigital number, since it uses as much as digits as its factorization.

255612231253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108000, while the sum is 37.

The spelling of 255612231253 in words is "two hundred fifty-five billion, six hundred twelve million, two hundred thirty-one thousand, two hundred fifty-three".