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2556352321331 is a prime number
BaseRepresentation
bin100101001100110010011…
…110001101011100110011
3100001101101120220002111212
4211030302132031130303
5313340402143240311
65234212210030335
7352455536131424
oct45146236153463
910041346802455
102556352321331
118a6163272376
123535312783ab
131570a8507583
148ba29d2564b
154676aed4c8b
hex2533278d733

2556352321331 has 2 divisors, whose sum is σ = 2556352321332. Its totient is φ = 2556352321330.

The previous prime is 2556352321307. The next prime is 2556352321333. The reversal of 2556352321331 is 1331232536552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2556352321331 - 222 = 2556348127027 is a prime.

It is a super-2 number, since 2×25563523213312 (a number of 26 digits) contains 22 as substring.

Together with 2556352321333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2556352321333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278176160665 + 1278176160666.

It is an arithmetic number, because the mean of its divisors is an integer number (1278176160666).

Almost surely, 22556352321331 is an apocalyptic number.

2556352321331 is a deficient number, since it is larger than the sum of its proper divisors (1).

2556352321331 is an equidigital number, since it uses as much as digits as its factorization.

2556352321331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 486000, while the sum is 41.

Adding to 2556352321331 its reverse (1331232536552), we get a palindrome (3887584857883).

The spelling of 2556352321331 in words is "two trillion, five hundred fifty-six billion, three hundred fifty-two million, three hundred twenty-one thousand, three hundred thirty-one".