Base | Representation |
---|---|
bin | 100101001100110010011… |
… | …110001101011100110011 |
3 | 100001101101120220002111212 |
4 | 211030302132031130303 |
5 | 313340402143240311 |
6 | 5234212210030335 |
7 | 352455536131424 |
oct | 45146236153463 |
9 | 10041346802455 |
10 | 2556352321331 |
11 | 8a6163272376 |
12 | 3535312783ab |
13 | 1570a8507583 |
14 | 8ba29d2564b |
15 | 4676aed4c8b |
hex | 2533278d733 |
2556352321331 has 2 divisors, whose sum is σ = 2556352321332. Its totient is φ = 2556352321330.
The previous prime is 2556352321307. The next prime is 2556352321333. The reversal of 2556352321331 is 1331232536552.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2556352321331 - 222 = 2556348127027 is a prime.
It is a super-2 number, since 2×25563523213312 (a number of 26 digits) contains 22 as substring.
Together with 2556352321333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2556352321333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278176160665 + 1278176160666.
It is an arithmetic number, because the mean of its divisors is an integer number (1278176160666).
Almost surely, 22556352321331 is an apocalyptic number.
2556352321331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2556352321331 is an equidigital number, since it uses as much as digits as its factorization.
2556352321331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 486000, while the sum is 41.
Adding to 2556352321331 its reverse (1331232536552), we get a palindrome (3887584857883).
The spelling of 2556352321331 in words is "two trillion, five hundred fifty-six billion, three hundred fifty-two million, three hundred twenty-one thousand, three hundred thirty-one".
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