2556411433 has 2 divisors, whose sum is σ = 2556411434. Its totient is φ = 2556411432.

The previous prime is 2556411401. The next prime is 2556411439. The reversal of 2556411433 is 3341146552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2333566249 + 222845184 = 48307^2 + 14928^2 .

It is a cyclic number.

It is not a de Polignac number, because 2556411433 - 2⁵ = 2556411401 is a prime.

It is a super-2 number, since 2×2556411433² = 13070478829546226978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2556411439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278205716 + 1278205717.

It is an arithmetic number, because the mean of its divisors is an integer number (1278205717).

Almost surely, 2^2556411433 is an apocalyptic number.

It is an amenable number.

2556411433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2556411433 is an equidigital number, since it uses as much as digits as its factorization.

2556411433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 34.

The square root of 2556411433 is about 50560.9674848099. The cubic root of 2556411433 is about 1367.3412539275.

Adding to 2556411433 its reverse (3341146552), we get a palindrome (5897557985).

The spelling of 2556411433 in words is "two billion, five hundred fifty-six million, four hundred eleven thousand, four hundred thirty-three".