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2556433101 = 3852144367
BaseRepresentation
bin1001100001100000…
…0001001011001101
320121011101020221110
42120120001023031
520213421324401
61101401122233
7120231215505
oct23030011315
96534336843
102556433101
1110a2049032
125b4189379
1331982aa11
141a3740a05
15ee6769d6
hex986012cd

2556433101 has 4 divisors (see below), whose sum is σ = 3408577472. Its totient is φ = 1704288732.

The previous prime is 2556433097. The next prime is 2556433163. The reversal of 2556433101 is 1013346552.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2556433101 - 22 = 2556433097 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2556433001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 426072181 + ... + 426072186.

It is an arithmetic number, because the mean of its divisors is an integer number (852144368).

Almost surely, 22556433101 is an apocalyptic number.

It is an amenable number.

2556433101 is a deficient number, since it is larger than the sum of its proper divisors (852144371).

2556433101 is an equidigital number, since it uses as much as digits as its factorization.

2556433101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 852144370.

The product of its (nonzero) digits is 10800, while the sum is 30.

The square root of 2556433101 is about 50561.1817603189. The cubic root of 2556433101 is about 1367.3451170858.

Adding to 2556433101 its reverse (1013346552), we get a palindrome (3569779653).

The spelling of 2556433101 in words is "two billion, five hundred fifty-six million, four hundred thirty-three thousand, one hundred one".

Divisors: 1 3 852144367 2556433101