Base | Representation |
---|---|
bin | 100101001100111101010… |
… | …100011100010110100011 |
3 | 100001101212021100002110022 |
4 | 211030331110130112203 |
5 | 313341240240412212 |
6 | 5234242230424055 |
7 | 352463206042505 |
oct | 45147524342643 |
9 | 10041767302408 |
10 | 2556534310307 |
11 | 8a6246a7338a |
12 | 35358220202b |
13 | 157107126863 |
14 | 8ba46179d75 |
15 | 4677be82772 |
hex | 2533d51c5a3 |
2556534310307 has 2 divisors, whose sum is σ = 2556534310308. Its totient is φ = 2556534310306.
The previous prime is 2556534310261. The next prime is 2556534310373. The reversal of 2556534310307 is 7030134356552.
It is a happy number.
2556534310307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2556534310307 - 214 = 2556534293923 is a prime.
It is not a weakly prime, because it can be changed into another prime (2556534310507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278267155153 + 1278267155154.
It is an arithmetic number, because the mean of its divisors is an integer number (1278267155154).
Almost surely, 22556534310307 is an apocalyptic number.
2556534310307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2556534310307 is an equidigital number, since it uses as much as digits as its factorization.
2556534310307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134000, while the sum is 44.
Adding to 2556534310307 its reverse (7030134356552), we get a palindrome (9586668666859).
The spelling of 2556534310307 in words is "two trillion, five hundred fifty-six billion, five hundred thirty-four million, three hundred ten thousand, three hundred seven".
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