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25569027611317 is a prime number
BaseRepresentation
bin1011101000001010000001…
…10011101101101010110101
310100112101010111102022200101
411310011000303231222311
511322410332032030232
6130214125451114101
75246205224461561
oct564050063555265
9110471114368611
1025569027611317
11816884455a053
122a4b547742931
1311361c234cb98
1464579463c6a1
152e51982711e7
hex174140cedab5

25569027611317 has 2 divisors, whose sum is σ = 25569027611318. Its totient is φ = 25569027611316.

The previous prime is 25569027611273. The next prime is 25569027611329. The reversal of 25569027611317 is 71311672096552.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17985139510321 + 7583888100996 = 4240889^2 + 2753886^2 .

It is a cyclic number.

It is not a de Polignac number, because 25569027611317 - 243 = 16772934589109 is a prime.

It is a super-2 number, since 2×255690276113172 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25569027611117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12784513805658 + 12784513805659.

It is an arithmetic number, because the mean of its divisors is an integer number (12784513805659).

Almost surely, 225569027611317 is an apocalyptic number.

It is an amenable number.

25569027611317 is a deficient number, since it is larger than the sum of its proper divisors (1).

25569027611317 is an equidigital number, since it uses as much as digits as its factorization.

25569027611317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4762800, while the sum is 55.

The spelling of 25569027611317 in words is "twenty-five trillion, five hundred sixty-nine billion, twenty-seven million, six hundred eleven thousand, three hundred seventeen".