Search a number
-
+
255716484710399 is a prime number
BaseRepresentation
bin111010001001001010100010…
…001110111111111111111111
31020112102020221111021220022222
4322021022202032333333333
5232004124330041213044
62303510310433155555
7104601622606251566
oct7211124216777777
91215366844256288
10255716484710399
117452a830116499
122481b6993bbbbb
13ac8bc65529c4b
144720a5b382bdd
151e86b8c8168ee
hexe892a23bffff

255716484710399 has 2 divisors, whose sum is σ = 255716484710400. Its totient is φ = 255716484710398.

The previous prime is 255716484710383. The next prime is 255716484710411. The reversal of 255716484710399 is 993017484617552.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 255716484710399 - 24 = 255716484710383 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (255716484712399) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127858242355199 + 127858242355200.

It is an arithmetic number, because the mean of its divisors is an integer number (127858242355200).

It is a 2-persistent number, because it is pandigital, and so is 2⋅255716484710399 = 511432969420798, but 3⋅255716484710399 = 767149454131197 is not.

Almost surely, 2255716484710399 is an apocalyptic number.

255716484710399 is a deficient number, since it is larger than the sum of its proper divisors (1).

255716484710399 is an equidigital number, since it uses as much as digits as its factorization.

255716484710399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 457228800, while the sum is 71.

The spelling of 255716484710399 in words is "two hundred fifty-five trillion, seven hundred sixteen billion, four hundred eighty-four million, seven hundred ten thousand, three hundred ninety-nine".