Base | Representation |
---|---|
bin | 111010001100110111000000… |
… | …111001000100010001111011 |
3 | 1020120022112100102201000221001 |
4 | 322030313000321010101323 |
5 | 232022304340420444143 |
6 | 2304223102424425431 |
7 | 104626152120543133 |
oct | 7214670071042173 |
9 | 1216275312630831 |
10 | 255970402124923 |
11 | 7461848a957202 |
12 | 24860941918277 |
13 | aca9ba00833a5 |
14 | 472d06816bac3 |
15 | 1e8d59e4e114d |
hex | e8cdc0e4447b |
255970402124923 has 2 divisors, whose sum is σ = 255970402124924. Its totient is φ = 255970402124922.
The previous prime is 255970402124891. The next prime is 255970402125007. The reversal of 255970402124923 is 329421204079552.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 255970402124923 - 25 = 255970402124891 is a prime.
It is not a weakly prime, because it can be changed into another prime (255971402124923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127985201062461 + 127985201062462.
It is an arithmetic number, because the mean of its divisors is an integer number (127985201062462).
Almost surely, 2255970402124923 is an apocalyptic number.
255970402124923 is a deficient number, since it is larger than the sum of its proper divisors (1).
255970402124923 is an equidigital number, since it uses as much as digits as its factorization.
255970402124923 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10886400, while the sum is 55.
The spelling of 255970402124923 in words is "two hundred fifty-five trillion, nine hundred seventy billion, four hundred two million, one hundred twenty-four thousand, nine hundred twenty-three".
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