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255970402124923 is a prime number
BaseRepresentation
bin111010001100110111000000…
…111001000100010001111011
31020120022112100102201000221001
4322030313000321010101323
5232022304340420444143
62304223102424425431
7104626152120543133
oct7214670071042173
91216275312630831
10255970402124923
117461848a957202
1224860941918277
13aca9ba00833a5
14472d06816bac3
151e8d59e4e114d
hexe8cdc0e4447b

255970402124923 has 2 divisors, whose sum is σ = 255970402124924. Its totient is φ = 255970402124922.

The previous prime is 255970402124891. The next prime is 255970402125007. The reversal of 255970402124923 is 329421204079552.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 255970402124923 - 25 = 255970402124891 is a prime.

It is not a weakly prime, because it can be changed into another prime (255971402124923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127985201062461 + 127985201062462.

It is an arithmetic number, because the mean of its divisors is an integer number (127985201062462).

Almost surely, 2255970402124923 is an apocalyptic number.

255970402124923 is a deficient number, since it is larger than the sum of its proper divisors (1).

255970402124923 is an equidigital number, since it uses as much as digits as its factorization.

255970402124923 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10886400, while the sum is 55.

The spelling of 255970402124923 in words is "two hundred fifty-five trillion, nine hundred seventy billion, four hundred two million, one hundred twenty-four thousand, nine hundred twenty-three".