Base | Representation |
---|---|
bin | 100101010000001101000… |
… | …111001101100001000101 |
3 | 100001201212020020000020021 |
4 | 211100031013031201011 |
5 | 313420410222040342 |
6 | 5240020203535141 |
7 | 352645460143435 |
oct | 45201507154105 |
9 | 10051766200207 |
10 | 2560020502597 |
11 | 8a777591a238 |
12 | 35419582a4b1 |
13 | 15754146a42c |
14 | 8bc971822c5 |
15 | 468d3063567 |
hex | 2540d1cd845 |
2560020502597 has 2 divisors, whose sum is σ = 2560020502598. Its totient is φ = 2560020502596.
The previous prime is 2560020502577. The next prime is 2560020502607. The reversal of 2560020502597 is 7952050200652.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2445051359556 + 114969143041 = 1563666^2 + 339071^2 .
It is a cyclic number.
It is not a de Polignac number, because 2560020502597 - 211 = 2560020500549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2560020502517) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1280010251298 + 1280010251299.
It is an arithmetic number, because the mean of its divisors is an integer number (1280010251299).
Almost surely, 22560020502597 is an apocalyptic number.
It is an amenable number.
2560020502597 is a deficient number, since it is larger than the sum of its proper divisors (1).
2560020502597 is an equidigital number, since it uses as much as digits as its factorization.
2560020502597 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 2560020502597 in words is "two trillion, five hundred sixty billion, twenty million, five hundred two thousand, five hundred ninety-seven".
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